Question

sum of three consecutive multiples of 11 is 363 find numbers

Answer 1

let the three consecutive numbers be
x , x+11 , x+11+11=x+22

their sum = 363
x+(x+11)+(x+22) = 363
=>3x+33 = 363
=>3x = 363-33
=>3x = 330
=>x = 330/3 = 110

so x = 110
x+11= 110+11= 121
x+22=110+22= 132

hence those three consecutive numbers multiple of 11 are : 110, 120, 132

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-sneha
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Answer 2

Let's take the first number = x 

Therefore, x + (x+11) + (x+22) = 363 

3x +33 = 363 

3x = 363 - 33 

3x = 330 

x = 330 / 3 

x = 110 


First number is 110 
Second number is 121 
Third number is 132