A girl for mass 40 kg jumps with a horizontal velocity of 5 metre second Om to a stationary cart with frictionless wheels the mass of a cart is 3 kg what is Har velocity as the cart start moving? assume that there is no external unbalanced force working in the horizontal direction
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use law of conservation of momentum
to find is v1+v2 as she get stick to it while jumping over it
to find is v1+v2 as she get stick to it while jumping over it
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Answer:
Mass of the girl = 40 kg
Mass of the cart = 3 kg
Velocity of the girl = 5 m/s
Velocity of the cart = 0 m/s
To Find :-
Velocity as the cart starts moving.
Solution :-
Firstly let's find the Mounmentum of girl
[P = mv]
Here,
P = Mounmentum
M = Mass
V = Velocity
P = 40 × 5
Hence, Mounmentum of girl is 200 kg m/s .
Now,
Let's add the Mounmentum of girl and cart
200 + 0 = 200 kg m/s
Let's find total mass
Total mass = 40 + 3 = 43 kg
Velocity=Mounmentum/mass
V = P/M
Velocity = 200/43
Hence :-
Velocity of cart is when start moving is 4.65 m/s.
@ananya
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