Question

A girl got out of her house at 10 am on Saturday. Her mother, who likes to measure time in seconds, told her to come back in 1.728 10^5 s. She came back at 9 am on Monday.​

Answer 1

Answer:

She came exactly on time

Step-by-step explanation

Given :

1.728*10^5 s =  172800 s

Divide the value twice by 60 to convert seconds into hours (or once by 180 )

172800/60 = 2880 minutes

2880/60 = 47 hours

Which shows that 47 hours from Sunday 10 am is 9 am on Monday .

Answer 2

(B) She came back 1 h before her time limit

Step-by-step explanation:

• Starting time of the girl =  10 am on Saturday
• The time when she was back = 9 am on Monday

The number of hours she was out = 1 hour less than two days $= 24+23 = 47$ hours

• The mother asked her to return in $= 1.728\times 10^5$ s

Converting the above time into hours

$1.728\times 10^5 s = \frac{1.728\times 10^5}{60}$ minutes $= 2.88\times 10^3$ minutes

$2.88\times 10^3$ minutes $= \frac{2.88\times 10^3}{60}$ hours = 48 hours

• So, according to her mother, she could be back by 10 am Monday, but she returned at 9 am Monday.

Hence, she was one hour earlier before her time limit.

[THE QUESTION IS INCOMPLETE. BUT, MOST PROBABLY IT IS:

A girl got out of her house at 10 am on Saturday. Her mother, who likes to measure time in seconds, told her to come back in1.728 x 10⁵ s. She came back at 9 am on Monday.

(A) She came back exactly on time.

(B) She came back 1 h before her time limit.

(C) She came back 2 h before her time limit.

(D) She came back 1 h after her time limit]