Question

a girl is 28 years younger than her father and sum of their ages is 50 years find their ages

Answer 1

The girl is 11 years old and the father is 39 years old . Hence the girl is 28 years younger than her father and their sum of ages is 50 years.

Both the requirement is fulfilled

Hope it helps

Answer 2

Let present age of Father be X year's.



Present age of daughter = ( X - 28 ) year's.



Sum of their ages = 50


X + X - 28 = 50


2X = 50 + 28



X = 78/2


X = 39 year's.


Present age of Father = X = 39 year's.


And,

Present age of daughter = X - 28 = 39 -28 = 11 year's.