Question

a girl of Feet 500 Newton has feet with the total area of 200 cm square. what pressure does she apply on the ground if she stands on both the feet ?​

Answer 1

Answer:

Hence, pressure exerted by both foot on the ground = 25000 Pascals

Explanation:

Given,

Force exerted by one foot, F = 500 N

Force exerted by two foot, F = 2 × 500 = 1000 N

Area of one foot, a = 200 cm^2 = 0.02 m^2

Area of two foot, a = 2 × 0.02 = 0.04 m^2

Let the pressure exerted by two foot be 'P'. Then,

P = F / a

=> P = 1000/0.04 = 25000 Pa

Hence, pressure exerted by both foot on the ground = 25000 Pascals

Answer 2

Solution-

Given:

• Force (F) = $\sf{500 N}$
• Area (A) =$\sf{200 {cm^2} = 200 × ({10^{-2}})^2= 200 × {10^{-4}}}$

We know that,

Pressure= $\sf\dfrac{Force}{Area}$

$\sf\:\:\:\:\:\:\:\:=\dfrac{500\:N}{200×{10^-4}m^2}$

$\sf\:\:\:\:\:\:\:\:=2.5×10^4N{m^{-2}}$

$\sf\:\:\:\:\:\:\:\:=25×10^3N{m^{-2}}$

Therefore, the pressure she applied on the ground is $\sf\red{25×10^3N{m^{-2}}}$