Question

A girl of mass 40kg jumps with the horizontal velocity of 5m/sec on to a stationary cart with friction less wheel the mass of cart is 3kg what is her velocity as moves of the cart there is no ex force unbalance force working in horizontal direction

Answer 1

Answer:

m1=40

m2=3

u1=3

u2=0

v1=v2=x

m1u1+m2u2= m1v1+m2v2

200+3×0=120 (v2)

200÷120=v2

1.666m/s

hope it helps

Answer 2

Answer:

Mass of the girl = 40 kg

Mass of the cart = 3 kg

Velocity of the girl = 5 m/s

Velocity of the cart = 0 m/s

To Find :-

Velocity as the cart starts moving.

Solution :-

Firstly let's find the Mounmentum of girl

[P = mv]

Here,

P = Mounmentum

M = Mass

V = Velocity

P = 40 × 5

Hence, Mounmentum of girl is 200 kg m/s .

Now,

Let's add the Mounmentum of girl and cart

200 + 0 = 200 kg m/s

Let's find total mass

Total mass = 40 + 3 = 43 kg

Velocity=Mounmentum/mass

V = P/M

Velocity = 200/43

Hence :-

Velocity of cart is when start moving is 4.65 m/s.

@ananya