Question

A girl of mass 50 kg jumps out of a rowing boat of mass 300 kg on to the bank, with a horizontal velocity of 3 m/s. With what velocity does the boat begin to move backwards? Please may someone help me....

Answer 1

Answer:

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Explanation:

Initial Momentum = Final momentum

0 = m1u1 + m2u2

u2 = -(m1 u1) / m2

= -(50 kg × 3 m/s) / (300 kg)

= -0.5 m/s

(-ve sign indicates that boat moves backwards)

Velocity of boat will be 0.5 m/s

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Answer 2

Answer:0.5m/s

Explanation:

By law of conservation of momentum.

m1×30 + m2×v = 0

50×30 + 300×v =0

300×v =-150

v = -150/300

v = -0.5 m/s

Here the negative sign for velocity indicates that the boat moves in opposite direction to the girls motion