Physics, asked by JayanthBeerus3498, 11 months ago

A girl of mass 50 kg runs up a flight of 20 States each measuring 15 CM in 25 seconds calculate the energy of girl G equal to 10 metre per second square

Answers

Answered by alishaalisha598
0

Answer:

Work done by girl=force*displacement

force=mass*acceleration due to gravity

force=50*9.8=490

displacement =no.stairs*height of each stairs

displacement=50*20=10

therefore work =f*d=490*10=4900J

power=work /time =4900/20=245J/S

Answered by ShivamKashyap08
21

{ \huge \bf { \mid{ \overline{ \underline{Correct \: Question}}} \mid}}

A girl of mass 50 kg runs up a flight of 20 Stairs each measuring 15 cm in 25 seconds calculate the energy of girl (g = 10 m/s²)?.

\huge{\bold{\underline{\underline{....Answer....}}}}

\huge{\bold{\underline{Given:-}}}

  • Mass of the girl (M) = 50kg.
  • Height of Stairs (x) = 15cm.
  • No. of stairs (n) = 20.
  • Acceleration due to gravity (g) = 10 m/s².
  • Time taken (t) = 25 seconds.

\huge{\bold{\underline{Explanation:-}}}

\rule{300}{1.5}

As we Know,

Work done:-

  • Work is defined as the scalar product of Force(F) and displacement(s).
  • Its S.I unit is Joules (J).

From, Work done formula,

\large{\boxed{\tt W = F.s}}

But, As here Force acting is through by The girl's weight.

  • F = W.
  • F = Mg

Substituting it,

\large{\tt \leadsto W = Mg \times s}

  • And The Displacement will be The Height to which the girl rises,
  • s = h

Now,

\large{\tt \leadsto W = Mgh \: -----(1)}

But we know

Energy is Defined as The capacity of Doing work

Therefore,

\large{\boxed{\tt E = Mgh}}

\rule{300}{1.5}

\rule{300}{1.5}

Now, Finding The Height to which the girl rises.

The Height can be Found out Through

\large{\boxed{\tt h = No. \:  of \: stairs \times Height \: of \: Stairs}}

\large{\tt \leadsto h = n \times x}

Substituting the values,

\large{\tt \leadsto h = 20 \times 15}

\large{\tt \leadsto h = 300 \: cm}

As The obtained Value is in Centimeters

It needs to be converted into Meters.

Therefore,

\large{\underline{\underline{\tt \leadsto h = 3m}}} \: \: \longrightarrow \tt 1m = 100cm

Now, Substituting the values in the Energy

\large{\boxed{\tt E = mgh}}

Substituting,

\large{\tt \leadsto E = 50 \times 10 \times 3}

\large{\tt \leadsto E  = 500 \times 3}

\huge{\boxed{\boxed{\tt E = 1500 \: J}}}

So, the Energy of the girl is 1500 Joules.

\rule{300}{1.5}

\rule{300}{1.5}

Extra Shots :-

Calculating The power of the Girl?

As we Know,

Power is Defined as rate of doing work.

From Definition we get,

\large{\boxed{\tt P = \dfrac{W}{t}}}

As we Know,

Energy = Work done

Work done (W) = 1500 J.

Substituting the values in Power Formula,

\large{\boxed{\tt P = \dfrac{W}{t}}}

Now,

\large{\tt \leadsto P = \dfrac{1500}{25}}

\large{\tt \leadsto P = \dfrac{\cancel{1500}}{\cancel{25}}}

\huge{\boxed{\boxed{\tt P = 60 \: W}}}

So, the Power of the Girl is 60 Watts.

\rule{300}{1.5}

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