Question

a girl starts from her home and walks 3m east then 4m south and then 5m vertically upwards. what is her magnitude of displacement from home?​

Answer 1

Answer:

displacement = √10 m

Explanation:

The girl walks 3 m east , then 4 m south and then 5 m vertically upward.

This means that she travels 1 m towards north along with the 4 m.

displacement is given by ,

AC² = 3²+1²

       =9+1

       =10

displacement = √10 m

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Answer 2

Answer:

The displacement from home is 7.07m

Explanation:

Given that,

The girl walks 3m east first.Therefore her displacement vector is 3i

Then,the girl walks 4m south.Therefore the displacement vector is 4j

Later,she walks 5m vertically upward.Therefore the displacement vector is 5k

The total displacement vector is sum of all individual displacement vectors

$displacement = 3i + 4j + 5k$

Magnitude is given as

$|d| = \sqrt{3 {}^{2} + 4 {}^{2} + 5 {}^{2} } = \sqrt{50} = 7.07m$

Therefore,the displacement from home is 7.07m

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