Question

a girl swim along the length of 80 in swimming pool and come back in 105 second find distance and displacement

Answer 1

So , girl move back and front

Net distance =80+80=160

Since final point and initial point are same ;

Displacement= final point - initial point = 0.

hope it is helpful to you.

Answer 2

$\huge\mathbb{Answer:-}$

$<b>$The girl goes back and forth;

So,

The net distance = 80 + 80

=160 m

For displacement;

Net displacement = Final point - initial point

Since the final point and the initial points are the same

Displacement = 0

So, the distance covered is 160m and the displacement is 0 m