Question

A girl walks 200 m towards east and then she walks 150 m towards north.
Find the distance of the girl from starting point.​

Answer 1

Answer:

Step-by-step explanation:

first the girl walks east then north forming a right angle triangle

therefore by Pythagoras theorem.

$200^{2}+ 150^{2} = x^{2}\\40000+22500=x^{2}\\62500=x^{2} \\250=x\\therefore distance from starting point is 250 meters$