Question

A girl walks 200 towards East and the she walks 150m towards North then the distance of the
girl from the starting point is ______

Answer 1

Step-by-step explanation:

At initial the girl started walking in the east for 200m

then she turns towards north and starts walking for 150m

this forms a right angled triangle

Let the triangle be ∆ABC

Angle ABC is 90 degree

:, BY PYTHAGORAS THEOREM

AB square + BC square = AC square

:, 200 sq + 150 sq =40000 +22500= 62500

there fore distance from the starting point is 250 m

Answer 2

Answer:

250m

Step-by-step explanation:

√(40000+22500)

=√(62500)

=250