a girl weighing 50kg is standing on pencil heels, each having an area of cross-section of 1cm. A elephant weighing 200kg and foot area of cross section of 250 cm standing on the floor which exerts more presure on the floor calculate the pressure exerted by her on the floor.
Answers
Answered by
0
Pressure = Force / Area
= mg / Area
Pressure on floor due to girl
P₁ = 2 × (50 × 9.8) / (π × (0.01)²)
= 3.1 × 10⁶ Pa
Pressure on floor due to elephant
P₂ = 4 × (200 × 9.8) / (π × (2.5)^2)
= 399.28 Pa
Q. Which exerts more presure?
Ans. Girl [∵ P₁ > P₂]
[Note: I assumed that cross section of heel and elephant’s foot is perfectly circular. Also, I multiplied pressure by 2 in case of girl and 4 in case of elephant because normal girl has 2 legs and normal elephant has 4 legs].
= mg / Area
Pressure on floor due to girl
P₁ = 2 × (50 × 9.8) / (π × (0.01)²)
= 3.1 × 10⁶ Pa
Pressure on floor due to elephant
P₂ = 4 × (200 × 9.8) / (π × (2.5)^2)
= 399.28 Pa
Q. Which exerts more presure?
Ans. Girl [∵ P₁ > P₂]
[Note: I assumed that cross section of heel and elephant’s foot is perfectly circular. Also, I multiplied pressure by 2 in case of girl and 4 in case of elephant because normal girl has 2 legs and normal elephant has 4 legs].
Similar questions