gun fires a bullet of mass 50 g. The bullet moving with a velocity of 100 m/s strikes a sand bag and gets embedded after travelling 10 cm. Calculate:- 1)The resistive force exerted by the sand on the bullet. 2)The time taken by the bullet to come to rest.
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Mass of bullet (m) = 50 g = 0.050 kg
initial velocity of bullet (u) = 100m/s
distance travelled by bullet (s) = 10 cm = 0.1 m
We know ,
v² - u² = 2 as
0 - (100)² = 2 x a x 0.1
-1000 /0.1 = 2a
-10000 = 2a
a = - 5000 m/s²
resistive force = m x a
= 0.05 x(- 5000)
= - 250 N
Time taken
v = u + at
0 = 100 - 5000 t
-100 /5000 = t
t = 0.02 seconds
initial velocity of bullet (u) = 100m/s
distance travelled by bullet (s) = 10 cm = 0.1 m
We know ,
v² - u² = 2 as
0 - (100)² = 2 x a x 0.1
-1000 /0.1 = 2a
-10000 = 2a
a = - 5000 m/s²
resistive force = m x a
= 0.05 x(- 5000)
= - 250 N
Time taken
v = u + at
0 = 100 - 5000 t
-100 /5000 = t
t = 0.02 seconds
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0
humko ni malum
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