Question

A girl weighing 80kgf wears sandals with heel of area of cross section 2cm². Calculate the pressure exerted by her on the floor.​

Answer 1

Answer:

here is the answer

Explanation:

on the floor. A sumo wrestler weighing 250 kgf stands on foot each of area of cross section 25 sq.cm. on the floor. compare the pressure exerted by them.

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Answer 2

Weight of girl = 80 kgf

∵ 1 kgf = 9.8 N,

∴ Weight of girl = 80 × 9.8 N = 784 N

And, P = F/A

∴ P = (784 × 10⁵ dyn)/(2 cm²)

⇒ P = 392 × 10⁵ Ba

⇒ P = 3.92 × 10⁷ Ba.

Therefore, pressure exerted by the girl is of 3.92 × 10⁷ Ba.