Question

A girl whose mass is 40 kg ,running at 6 m/s jumps on to a 20 kg cart travelling in the same direction at 3 m/s. What is the common velocity after the interaction?__________



plz answer.....very urgent

Answer 1

Answer:

Given : M

girl

=40 kg u

girl

=5 m/s M

cart

=3 kg

Initial velocity of cart u

cart

=0

Let the final velocity of cart be V.

Applying conservation of linear momentum : P

i

=P

f

Or M

girl

u

girl

+M

cart

u

cart

=(M

girl

+M

cart

)V

Or 40×5+3×0=(40+3)V

⟹ V=

43

200

m/s

Explanation:

Hope you will be helpful....

Answer 2

Explanation:

Given : M

girl

=40 kg u

girl

=5 m/s M

cart

=3 kg

Initial velocity of cart u

cart

=0

Let the final velocity of cart be V.

Applying conservation of linear momentum : P

i

=P

f

Or M

girl

u

girl

+M

cart

u

cart

=(M

girl

+M

cart

)V

Or 40×5+3×0=(40+3)V

⟹ V=

43

200

m/s