Question

A girl with a mass of 60 kg jump with a horizontal velocity of 6 m/s onto a stationary caryvwith fractional wheel .the mass of the cart is 6kg .what is her velocity as the cart start moving .find using conservation of momentum

Answer 1

M1=60kg

U1=6m/s

M2=6kg

U1=0m/s(the cart is stationery)

V1=V2(the girl is jumping onto the cart ,therefore their velocity is equal)

M1U1 +M2U2 = M1V1+M2V2( law of conservation of momentum)

360=V1 (M1+M2)

360=V1 (66)

V1=360/66

V1=5.4m/s