a given figure O is the centre of the circle PQ is a chord of the circle and R is any point on the circle if angle prq is equal to L and angle o p q is equal to M then find l + m
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O is the centre of the circle PQ is a chord of the circle and R is any point on the circle if angle prq is equal to L and angle o p q is equal to M
∠POQ = 2∠PRQ
⇒ ∠POQ = 2l
In △PQO, OP = OQ = r
⇒ ∠OQP = ∠OPQ = m
Also, ∠OPQ + ∠OQP + ∠POQ = 180°
⇒ m + m = 2l = 180°
⇒ 2(l + m) = 180°
⇒ l + m = 90°
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