Question

An electric bulb is connected to a 220 V generator. The current flowing is 2 ampere. Find the power of the bulb and resistance of it's filament

Answer 1

Hey mate here is your answer

V = 220V

I = 2A

Power of the bulb is

P = VI

  = 220 x 2 = 440w

Resistance of the filament is

R = V/I

   = 220/2

    = 110

Hope it helped you :)

Answer 2

Given,

1. Electricity provided by the generator(V) = 220V
2. Current flowing through the bulb(I) = 2 ampere

To find,

1. Power of the bulb
2. Resistance of the filament of the bulb

Solution,

Using the formula for power,

Power(P) = VI = 220 × 2 = 440 W

Now, calculate the resistance of the filament of the bulb using its formula.

Resistance(R) = $\frac{V}{I}$ = $\frac{220}{2}$ = 110 ohm.

Hence, the power of the bulb is 440 W and the resistance of its filament is 110 ohm.