Question

A given force (F) displaces an object through a distance 's' in its own direction and then in a direction inclined at 60°. What is the ratio of the work done in the two cases?
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Answer 1

Answer:

1st case :W1 = f . s = fs cos0 = fs

2nd case W2 = f.s = fs cos60 = fs/2

therefore W1/W2 = 2

Explanation:

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