water is flowing through a cylindrical pipe of cross
Attachments:
Answers
Answered by
24
In this question we will apply equation on countinity
aV^2=constant
if we half the diameter then areas of cylinder will become 1/4
0.09 pi × (1)^2 = 0.09 pi/4 × v
v= 4 m/s
aV^2=constant
if we half the diameter then areas of cylinder will become 1/4
0.09 pi × (1)^2 = 0.09 pi/4 × v
v= 4 m/s
Answered by
12
mark it as brainliest
Attachments:
Similar questions