Question

A given line has the equation 2x + 12y = −1. What is the equation, in slope-intercept form, of the line that is perpendicular to the given line and passes through the point (0, 9)? y = ( )x + 9

Answer 1

here in given eqn m=-2/12=-1/6

so perpendicular slope=6

so required eqn passing through (0,9)is y-9=6x

6x-y=-9

Answer 2

The slope-intercept form of a linear equation is:

y = mx +c 

Where 

m = slope

c =  intercept

2x + 12y = −1

12y = -2x – 1

y = -1/6y – 1/12

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The line that is perpendicular to this line will have a slope = 6

Note: The product of the slopes of two perpendicular lines = -1

Equation of the second line:

y – 9 = 6(x – 0)

y – 9 = 6x

y = 6x + 9