Question

A given mass of a gas occupies 143cm3 at 27degreee Celsius and 709mmHg pressure. What will be its volume at 300k and 280mmHg pressure?

Answer 1

if the gas is ideal than

we can use P1V1/T1=P2V2/T2

709×143/300=280×V2/300

V2=709×143/280 cm^3

Answer 2

The volume at 300k and 280mmHg pressure is $362cm^3$

Explanation:

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 709 mm Hg

$P_2$ = final pressure of gas = 280 mmHg

$V_1$ = initial volume of gas = $143cm^3$

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $27^oC=273+27=300K$

$T_2$ = final temperature of gas = 300 K

Now put all the given values in the above equation, we get:

$\frac{709mmHg\times 143cm^3}{300K}=\frac{280mmHg\times V_2}{300K}$

$V_2=362cm^3$

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