Question

A given solution of NaOH contains 2g of NaOH per liter of a solution. Calculate the molarity the a solution

Answer 1

Molar mass of NaOH = 23+16+1=40g
so 1mole = 40g
2g=1/40×2 moles =1/20moles

Molarity = moles ÷ volume of solution (in l)
=1/20÷1
=0.05M

HOPE IT HELPS..... :-)

Answer 2

Answer: 0.05M

Explanation: Molarity : It is defined as the number of moles of solute present in one liter of solution.

$Molarity=\frac{\text{given mass of compound}}{\text{molar mass of compound}\times \text{volume of solution is L}}$

Given mass of $NaOH$= 2g

Molar mass of $NaOH$ = 40g/mol

Volume of solution = 1L

$Molarity=\frac{2g}{40g/mol\times 1 L}=0.05moles/L=0.05M$