Question

A gives 0.2 of his money to B, B gives 0.3 of what he gets to C and C
gives 0.1 of what he gets to D. Thus D gets Rs. 30. Find A's money.​

Answer 1

Answer:

a money is 5000 rupees

Step-by-step explanation:

let a has money be y then

he gave b , y×0.2

then b to c , y×0.2×0.3

then c to d , y×0.2×0.3×0.1

now this equal to 30 rupees

now y×0.2×0.3×0.1 = 30

0.006y = 30

y = 5000

hence a has 5000 rupees

Answer 2

A had 5000 rupees.

Given,

A gives 0.2 of his money to B

B gives 0.3 of what he gets to C

C gives 0.1 of what he gets to D

D gets Rs 30

To Find,

Money A had

Solution,

Let the money A had to be 'x'

According to the question,

B got 0.2x

C got 0.3 of 0.2x

Thus, C got 0.3(0.2)x

C got 0.06x

D got 0.1 of 0.06x

Thus, D got 0.1(0.06)x

D got 0.006x

Also, D got 30 rupees, so we can say that,

0.006x = 30

x = $\frac{30}{0.006}$

x = 5000

Hence, A had 5000 rupees.

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