A glass ball moving on horizontal surface strikes with wall and rebounds with same speed of 2 m/s. The magnitude of change in velocity will be
Answers
Answered by
0
Explanation:
initial velocity=2m/s in x direction
final velocity= -2m/s in x direction
change in velocity= final velocity- initial velocity
= -2-2= -4 m/s
Therefore, the magnitude will be 4m/s
Answered by
0
Answer:
4m/s is the correct answer
Explanation:
To get the explanation please open the above image
hope it helps u
If it helps u please mark me as brainliest
Attachments:
Similar questions