A glass electrode- calomel electrode assembly shows an emf of 212 mV with pH= 4 buffer solution and -30mV with pH= 9.2 buffer solution. Find the pH of the test solution if it shows an emf of 120 mV. Also find E0 G if ESCE = 0.2422 V
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Explanation:Ecell= (E0G-0.2422)-0.0595pH
E=A+B x PH
A- y-intercept B-slope
212=A+Bx4 --(1)
-30 =A+Bx9.2 --(2)
On solving
B = -242/5.2= -46.53
A= 398.12V
pH of test solution = (120-398.12)/-46.53 = 5.97
E0 G=0.39812+0.2422= 0.6403 V
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