Question

A glass is filled with milk such that the weight of glass alone is 25% of its weight
when it is filled with milk. Now some of the milk is removed from the glass and now
the weight of glass along with remaining milk is 50% of the original total weight.
What part of the milk was removed from the glass?​

Answer 1

Given:

When filled with milk, the weight of the glass is 25% of the total weight.

When it is 50% filled, the weight of the glass is 50% of the total weight.

To Find:

The amount of milk that was removed (In percentage)

Solution:

Define x:

Let the weight of the glass be x

Find the weight of milk as part of the total weight:

Percentage of the weight of the milk = 100 - 25

Percentage of the weight of the milk = 75%

Find the weight of remaining milk as part of the total weight:

Remaining milk = 50% - 25%

Remaining milk = 25% of the total weight

Find the amount of milk that was removed:

Milk removed = 75 - 25

Milk removed = 50%

Answer: 50% of the milk was removed.

Answer 2

Answer:

2/3

Step-by-step explanation:

let total weight of glass with milk = 100%

weight of glass alone is 25% so weight of milk will be 75%

Now,

When milk is removed and 50% of the total weight remains

Weight of remaining milk = 50% - 25% = 25%

As we have been asked to find the part of the milk that was removed from the glass so,

## (previous weight% of milk - present weight% of milk) /previous weight% of milk

i.e.  (75-25)/75 = 2/3

Reason - Usually when we are asked to find the change% we use this formula"##" but here we were asked for fractional part so we dont

have to multiply it by 100.

NOTE - This answer is 100% correct and that 50% or 1/2 is incorrect