Physics, asked by Unickgaming, 3 months ago

A glass paper-weight (n =1.5) of radius 3 cm has a tiny air bubble trapped inside it. Closest distance of the bubble from the surface is 2 cm. Where will it appear when seen from the other end (from where it is farthest)?

Answers

Answered by subhamrout2019
0

Answer:

Explanation:

Using the formula for refraction through curved surfaces, vN2−uN1=RN2−N1

v1−−31.5=−51−1.5

v1+0.5=0.1

v1=−0.4

v=−410=−2.5cm

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