A glass paper-weight (n =1.5) of radius 3 cm has a tiny air bubble trapped inside it. Closest distance of the bubble from the surface is 2 cm. Where will it appear when seen from the other end (from where it is farthest)?
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Answer:
Explanation:
Using the formula for refraction through curved surfaces, vN2−uN1=RN2−N1
v1−−31.5=−51−1.5
v1+0.5=0.1
v1=−0.4
v=−410=−2.5cm
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