a glass plate is of length 2.0cm and width 1.5 cm .the maximum probable error in measuring the area of the plate is
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4
Answer:
Assuming that the glass plate is rectangular and the area of one side is asked.
In multiplication of quantities, RELATIVE errors get added up.
Least count is taken to be the error in this case.
Relative error in length
= ΔL/L
= 0.1/3.5
= 1/35
Relative error in width
= ΔW/W
= 0.1/1.5
= 1/15
Now, Relative error in area
ΔΑ/A = ΔL/L + ΔW/W
= 1/35+1/15
= 2/21
Maximum possible Error in area
= ΔA/A × A
= 2/21 × (1.5 × 3.5)
= +0.5 or -0.5 cm^2
Answered by
1
Explanation:
0.35 cm^2
the correct answer
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