Question

A glass slab has concave surface of radius of curvature 2.0 cm. The glass has refractive index of 1.5 If a point object is placed on axis in air at a distance of 18 cm from concave face, find the position & nature of the image

Answer 1

The image is at - 7.7 cm and the nature of the image is virtual and upright

Step-by-step explanation:

Given data:

R = 2.0 cm

n1 = 1

n2 = 1.5

u = 18 cm

v = ?

Refraction through spherical enter face

From medium 1 to 2 of refractive index n1 and n2

n2/v - n1/u = n2 - n1/R

1.5/v - 1/-18 = 1.5 -1/2

1.5/v = 0.5/2 + 1/-18

1.5/v = 0.5/2 - 1/18

1.5/v  = 4.5-1/18 = - 3.5/18

v = 1.5 x - 18/3.5

v = - 7.7

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