Question

A glass slab of thickness 3cm and refractive index 1.5 is placed on a paper.A person looks at it from a distance of 5cm above the paper.At what distance(in cm) from the person does the paper appear to be
options are
1,2,3,4....
(answer it as soon as possible)

Answer 1

given , refractive index 1.5
thickness of slab = 3 cm
distance of person from the paper = 5 cm
therefore, the actual real depth is =5-3=2

we know that ,

apparent depth / real depth = relative refractive index

therefore , the apparent depth is 3 cm

hope it helps you. (;

Answer 2

Given , refractive index 1.5

thickness of slab = 3 cm

distance of person from the paper = 5 cm

therefore, the actual real depth =5-3=2

we know that ,

apparent depth / real depth = relative refractive index

Then apparant depth =d/n =3/(3/2)=2

So the distance of the mark will appear is 2+2=4

Answer is 4