Physics, asked by kebirungisarah5, 6 months ago

a golf ball accelerates off a tee at 15m/s2 changing its velocity from 0m/s to 50m/s down. how long did the golf accelerate?​

Answers

Answered by Anonymous
83

\huge \underline \green{\sf{ Answer :- }}

Given :

Acceleration of Golf Ball (a) = 15 m/s²

Velocity of ball changes from 0 m/s to 50 m/s

To Find :

Time taken by golf ball to accelerate

Explanation :

The velocity of the ball changes from 0 m/s to 50 m/s, it means that the ball was initially at rest and the initial velocity of the ball will be taken as 0 m/s. Where are finally velocity of ball was 50 m/s ,So final velocity is 50 m/s. Acceleration of the ball is given as 15 m/s² .

We, will be using here Kinematics Equations, we can find time taken by ball to accelerate by using 1st equation of Motion or Kinematics

★ v=u+at

Where,

v is final velocity

u is initial velocity

a is acceleration

t is time interval

Solution :

Use 1st equation of motion :

⟹ v=u+at

⟹v−u = at

⟹t=av−u

⟹ t=1550−0

⟹t=1550

⟹t=3.3

\small \underline  {\sf{therefore \ ∴  \ Time \ taken \  by  \ golf  \ ball  \ to \ accelerate \ is \  3.3s }}

Answered by BrainlyRonaldo
78

Given

A golf ball accelerates off a tee at 15 m/s² changing its velocity from 0 m/s to 50 m/s down

To Find

How long did it take the golf ball to accelerate

Solution

We know that

Equation of motion

\sf \longrightarrow v=u+at

Here

  • u = initial velocity
  • v = final velocity
  • a = acceleration
  • t = time

Units

  • u = metres per second (m/s)
  • v = metres per second (m/s)
  • a = metres per second squared (m/s²)
  • t = seconds (s)

According to the question

We are asked to find how long did it take the golf ball to accelerate

Therefore

We must find "t"

Hence

\sf \longrightarrow t=\dfrac{v-u}{a}

Given that

A golf ball accelerates off a tee at 15 m/s² changing its velocity from 0 m/s to 50 m/s down

Hence

  • u = 0 m/s
  • v = 50 m/s
  • a = 15 m/s²

Substituting the values

We get

\sf \longrightarrow t=\dfrac{50-0}{15} \ s

\sf \longrightarrow t=\dfrac{50}{15} \ s

On further simplification

We get

\sf \longrightarrow t=3.333 \ s

Therefore

\sf \longrightarrow t \approx 3.3 \ s

Hence

Time taken by the golf ball to accelerate = 3.33 seconds

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