Question

A golf ball is hit from the ground and represented by the equation
​ h(t)=−16t2+64t+80
​where h(t) is the height after t seconds. How long does it take for the golf ball to this the ground?

Answer 1

Step-by-step explanation:

Given:

h(t) =16t^2+64t +80

To Find:Time taken to reach the ground

Solution :

As it will the ground after returning from the height hence h=0

$h(t) = 16 {t}^{2} + 64t + 80 \\ \: \: \: \: \: \: \: \: \: 0= 16( {t}^{2} + 4t + 5) \\ \: \: \: \: \: \: \: \: \: \: 0 = {t}^{2} + 4t + 5$

There Will not be real solution