Question

A golfer hits a ball of mass 45g at a speed of 40m/s. The golf club is in contact with the ball for 3s. Calculate the average force applied by the club on the ball.​

Answer 1

Mass m = 0.045 kg, 
Initial Velocity vi = 0, 
Final Velocity vf = 40m/s
Impulsive Force  F = ma =
$m \frac{vf - vi}{t}$

= 0.045 ×40/0.003
    = 600N.
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Answer 2

Answer:

Explanation:

Concept:

Impulse Force:

• A force that operates on an item impulsively does so for a brief length of time.

• An impulsive force is predominantly generated in a collision when one or more of the objects involved in the collision experience a change in velocity or momentum.

• In contrast to non-impulsive forces, which steadily continue a body's motion, impulsive forces work on a body to temporarily modify its state of motion.

• A driving body in an unanticipated collision with another is an impulsive force, as opposed to the weight of the body, which is a non-impulsive force.

Given:

               Mass (m)  = 45g =0.045kg

               Initial velocity (Vi)= 0

               Final velocity (Vf)= 40m/s

               Time(t) = 0.003s

Find:

               To find the average force applied by the club on the ball

Solution:

              Impulse force = ma

               =m(Vf-Vi)/t

               =0.045(40 - 0)/0.03

               =600N

Average force applied by the club on the ball is 600N

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