A grampophone turn table rotating at an angular velocity 3rad/s,stops after one revolution .find the angular retardation
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Hi,
Given , wo= 500 rpm = 500 /60 rotations per second = 25/3 rps
time = 10 seconds
So, w = 0 = wo+t,
= – 25/ 30 rotations / s2= -5/6 rotations / s2
Now,= wo t+ 0.5t2
So,= (25/3) 10 + 0.5 (-5/6) 102= 125/3 rotations.
thanks
Given , wo= 500 rpm = 500 /60 rotations per second = 25/3 rps
time = 10 seconds
So, w = 0 = wo+t,
= – 25/ 30 rotations / s2= -5/6 rotations / s2
Now,= wo t+ 0.5t2
So,= (25/3) 10 + 0.5 (-5/6) 102= 125/3 rotations.
thanks
preet191:
i need angular retardation brother
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