Question

A graph of square of velocity against the square of acceleration of a given simple harmonic motion is​

Answer 1

Answer :

Solution :

x=Asinωt

v=dx/dt=Aωt=ωA^2−x^2−−−−−−−√

a=dv/dt=−Aω^2sinωt

=dv/dt=−ω^2x

But x=−1/ω^2

v=ωA^2−a^2/ω^4−−−−−−−√

or v^2=ω^2(A^2−a^2/ω^4)                                                                                    

HOPE THIS HELPS U!!