Question

A grinding machine whose wheel has a radius of - is rotating at 2.5 rev/sec. A tool to be sharpened
is held against the wheel with a force of 40N. If the coefficient of friction between the tool and
wheel is 0.2, power required is
1) 40 W
2) 4W
3) 8W
4) 10W​

Answer 1

Answer:

40

Explanation:

Given A grinding machine whose wheel has a radius of 1/π is rotating at 2.5 rev/sec. A tool to be sharpened  is held against the wheel with a force of 40 N. If the coefficient of friction between the tool and  wheel is 0.2, power required is

Given wheel has a radius r = 1/π , number of revolutions per sec N = 2.5 , force F = 40 N, coefficient of friction μ = 0.2

We know that torque = T = μ F r  

Also we know that Power = 2 π N T

                                          = 2 x π x 2.5 x 0.2 x 40 x 1 / π

                                          = 40 watts

Answer 2

Answer:

40w

Explanation:

We know that torque = T = μ F r  

Also we know that Power = 2 π N T

                                         = 2 x π x 2.5 x 0.2 x 40 x 1 / π

                                         = 40 watts