Question

A ground in the shape of parallelogram the height is 14m and base is 8m find the cost of levelling the ground at the rate of$15 per sq m

Answer 1

Answer :-

$ 1,680

Given :-

b = 8 m

h = 14 m

To find the cost of levelling the ground at the rate of $ 15 /m².

Solution:-

First we have to find the area which have to be levelled.

Area of parallelogram is given by :-

$\huge \boxed{A = b \times h }$

put the given values,

→$A = 8 \times 14$

→$A = 112 m^2$

Now,

Cost of levelling of 1 m² ground is $ 15.

Cost of levelling of 112m² cost is

= 15 × 112

= $ 1,680

hence,

The cost of levelling the ground will be $ 1,680.

Answer 2

hello there

Step-by-step explanation:

Question:. A ground in the shape of parallelogram the height is 14m and base is 8m find the cost of levelling the ground at the rate of$15 per sq m?

Solution:

In the question it is given:

コ: Base (b)= 8 m

コ: Height (h)= 14 m

To find : cost of levelling the ground ( parallelogram) @ Rs 15 per sq. metre.

Note: To find the cost , Firstly it is necessary to find the area of the parallelogram

So,

Area of parallelogram is given by:

$= > </strong><strong>A</strong><strong> = </strong><strong>b</strong><strong> \times h$

Now ,

[ putting the value of the variables in the formulae accordingly. ]

■ Area = 8 m × 14 m

■ Area(A) = 112 m×m

So, The area of the parallelogram is = 112 sq. m (m×m)

Also, it is given that for levelling the ground 1 sq. m costs Rs 15

Therefore, 112 sq. m will cost :

■ ( 112 × 15 ) Rs

■ 1680 Rs

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Hope it helps

Thank you!