Math, asked by vashu1394, 1 year ago

A Group consists of 12 persons, of which 3 are extremely patient, other 6 are extremely

honest and rest are extremely kind. A person from the group is selected at random.

Assuming that each person is equally likely to be selected, find the probability of

selecting a person who is (i) extremely patient (ii) extremely kind or honest. Which of

the above values you prefer more?​

Answers

Answered by Vedant250204
2

THANKS FOR THE QUESTION

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TOTAL PEOPLE- 12

EXTREMELY PATIENT- 3

EXTREMELY HONEST- 6

EXTREMELY KIND- 3

I) 3/12 = 1/4 or 25%

II) 9/12 = 4/3 or 75%

HOPE IT HELPS

PLZ MARK BRAINLIST


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Answered by peaceloverpeace1
3

Answer:

Step-by-step explanation:

Total persons = 12

Extremely kind = 12-9 = 3

Extremely honest = 6

Extremely patient = 3

(1). 3/12 = 1/4

(2). (6+3)/12 = 9/12 = 3/4

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