Question

In a quadrilateral ABCD. AB = 50cm , BC =60 cm , CD=30 cm ,AD= 90 cm and BD =70 cm. Find its area...

Answer 1

s = a + b + c \ 2 (For triangle ABD)

= 90 + 50 + 70 \ 2

= 210 \ 2

= 105 cm

Area = whole root of 105 (105 - 90)(105 - 50)(105 - 70 )

= whole root of 105 (15)(55)(35)

= 525√11 sq.cm

For triangle BCD

s = a + b + c \ 2

= 70 + 60 + 30 \ 2

= 160 \ 2

= 80 cm

Area = whole root of 80 (80 - 70)(80 - 60)(80 - 30)

= whole root of 80 * 10 * 20 * 50

= 200√10 sq.cm

Therefore total area = (525√11 + 200√10) sq.cm

SORRY can't solve further .