A group of buffaloo and the duck , the number of legs are24 more than the twice the heads , what is the no. of buffaloo in tbe group
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the answer is 12......
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Let the number of buffaloes be x and the number of ducks be y
=> 4x + 2y = 2 (x + y) + 24
=> 2x = 24 => x = 12
=> 4x + 2y = 2 (x + y) + 24
=> 2x = 24 => x = 12
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