a group of people decided to complete a work in 13 days but 6 men were absent. so that the work was finished in 15 days. what is the original number of men.
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let x be the original no. of men
then,
x men can do the job in 13 days
1 men can do the job in (13×X) days
therefore
(X-6) man can do job in (13×X)/X-6 days
By the question, (13×X)/X-6 = 15
or, 13×X= 15(X-6)
or, 13×X= 15×X-90
or, 90= 15×X-13×X
or, 90=2×X
or X=90/2=45.
hence the original no. of men = 45.
then,
x men can do the job in 13 days
1 men can do the job in (13×X) days
therefore
(X-6) man can do job in (13×X)/X-6 days
By the question, (13×X)/X-6 = 15
or, 13×X= 15(X-6)
or, 13×X= 15×X-90
or, 90= 15×X-13×X
or, 90=2×X
or X=90/2=45.
hence the original no. of men = 45.
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