Question

A group of students of class X visited India Gate on an education trip. The teacher and students had interest in history as well. The teacher narrated that India Gate, official name Delhi Memorial, originally called All-India War Memorial, monumental sandstone arch in New Delhi, dedicated to the troops of British India who died in wars fought between 1914 and 1919.The teacher also said that India Gate, which is located at the eastern end of the Rajpath (formerly called the Kingsway), is about 138 feet (42 metres) in height.
Q11.What is the angle of elevation if they are standing at a distance of 42m away from the monument?
(A) 30 º (B) 45 º (C) 60 º (D) 0 º
Q12. They want to see the tower at an angle of 60 . So, they want to know the distance where they should stand and hence find the distance.
(A) 25.24 m (B) 20.12 m (C) 42 m (D) 24.64 m
Q13. If the altitude of the Sun is at 60 , then the height of the vertical tower that will cast a shadow of length 20 m is
(A) 20√3 m (B) 20/√3 m (C) 15/√3 m (D) 15√3 m
Q14. The ratio of the length of a rod and its shadow is 1:1 . The angle of elevation of the Sun is
(A) 30º (B) 45 º (C) 60 º (D) 90º
Q15. The angle formed by the line of sight with the horizontal when the object viewd is below the horizontal level is (A)Corresponding angle (B)Angle of elevation (C)Angle of depression (D)Complete angle.​

Answer 1

Answer:

1. b) 45°

2. a) 25.24 m

3. a) 20√3 m

4. b) 45°

5. a) corresponding angle

HOPE THE ANSWER HELPS

Answer 2

Answer:

The answers are

Q11)  (B) 45°

Q12)   (D)24.64m

Q13)  (A)20 $\sqrt{3}$ m

Q14)  (B) 45°

Q15)  (B) Angle of elevation is the answer

Step-by-step explanation:

Q11) to find the angle of elevation

   tanθ = $\frac{height of the tower}{distance from the tower}$

            = $\frac{42}{42}$

        θ =tan (1) = 45°

   (B) 45° is the answer

Q12) to find distance

            tan60°  = $\frac{height of the tower}{distance}$

                       = 42 / distance

              $\sqrt{3}$     = 42 / distance

           distance = 42 /  $\sqrt{3}$

                           = 24.64 m

   (D)24.64m is the answer

Q13) to find the height of the vertical tower

              tan60°  = $\frac{height of the tower}{distance}$

                     $\sqrt{3}$  = height of the tower / 20

                height of the tower = 20 $\sqrt{3}$ m

(A)20 $\sqrt{3}$ m is the answer

Q14)  to find the angle of elevation of the sun

                tanθ = $\frac{height of the tower}{distance from the tower}$

                         = 1/1 ( ∵the ratios are in 1:1)

                     θ  = tan(1) = 45°

(B)  45°  is the answer

Q15)  The angle formed by the line of sight with the horizontal when the object viewed  below the horizontal level is ANGLE OF ELEVATION .

(B) Angle of elevation is the answer