Question

the base of an isosceles triangle 48 cm and its equal side is 30 com find the area​

Answer 1

Answer:

2s = 48+30+30 = 108, or s = 54

Area = [s(s-a)(s-b)(s-c)]^0.5

= [54(54–48)(54–30)(54–30)]^0.5

= [54x6x24x24]^0.5

= 18x24 = 432 sq cm.

Method 2: Altitude on the base = [30^2–24^2]^0.5 = [54x6]^0.5 - 18 cm.

Area of the triangle = 48*18/2 = 432 sq cm.

There are some more methods besides these two.