A-—>2B +C the t1/2=24min if the initial pressure of A is 400mmHg in a closed vessel the pressure of the reaction mixture after expiry of 48min will be
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A(g)⟶2B(g)+C(s)
P0. 0
(P0-P) 2p
t1/2 =24 min,
400−P=100
P=300
∴ The pressureof the reaction mixture after expiry time =P0+P=400+300=700. mm
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