Question

a Gulab Jamun contains sugar syrup up to about 30% of its volume find approximately how much syrup would be found 45 Gulab Jamun is shaped like a cylinder with two hemispherical ends with length 5 cm and diameter 2.8 CMit's urgent please fast ​

Answer 1

Here is your answer:

       Therefore, radius of cylindrical part=radius of hemispherical part

   =r=2.8÷2=1.4cm

Now,

   Height of cylindrical part,

    h=pq-(pr+sq)

    =5-(1.4+1.4)

    =5-2.8

     =2.2cm

Hence,

 Volume of one gulabjamun =2× volume of cylindrical part

  2×(2/2πr*3)+πr*2h=4/3πr*3+πr*2h

 =22/7×14/14(4/3×14/10+22/10

  =22×1/5×7/5(28/15+11/5)

  =154/25×61/15

  =9394/375cm*2

 Now,

      45×9394/375

       =3×9394/25

        =28182

     1127.28cm*3

For 30℅syrup

  1127.28×30/100

  =1127.28×3/10

   =338.184

I hope this will help you...

Answer 2

radius of the cylinder part r=1.4cm

length of the cylinder part,h=(5-2×1.4)=2.2cm

Volume of one gulab jamun

=volume of 2 hemispherical parts+volume of the cylindrical part

=>(2×2/3πr³+πr²h)=(4/3πr^3+πr²h)

=>πr²(4/3r+h)=[22/7×1.4×1.4×(4/3×1.4+2.2)]cm³

=>(6.16×12.2/3)cm³=(75.152/3)cm³

Volume of 45 gulab jamun

=(75.152/3×45)cm³=1127.28cm³

Volume of the syrup

=30% of 1127.28cm³

=30/100×1127.28cm³

=338.184cm³
Hence,45 gulabjamuns contain approximately 338 cm³ of syrup.

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