Question

How far will a marble fall in 10.8 seconds if dropped out of an airplane?

Answer 1

Given:

Time = 1..8 seconds

To find:

Distance covered by the marble when dropped out of the airplane.

Solution:

We will use the formula :

s = ut + 1/2at²

Where s = distance covered

u = initial velocity

a = acceleration

t = time taken

Since the marble experiences acceleration due to gravity therefore a = 9.8 m/s².

Initial velocity of the marble = 0

Putting the values we get:

s = 0 + 1/2*9.8* (10.8)²

s = 571.5 m

Therefore the marble will fall 571.5 meters in 10.8 seconds.