Question

A gun is fired with a muzzle velocity of 500 m/s at an angle of 36.87 degrees above the horizontal a. What is the initial horizontal and vertical velocities? b. How long is the bullet in the air? (Assume level ground.) C. Graph the acceleration in the x and y direction as a function of time.​

Answer 1

Explanation:

Explanation:Horizontal range of bullet is 30 m.

Explanation:Horizontal range of bullet is 30 m.Using range formula, R= gu 2 sin2θ =30or sin2θ= (100)

2θ=0.03Therefore, θ=0.015 rad

2θ=0.03Therefore, θ=0.015 radIn ΔOAP,tanθ= OPAP ⇒AP=OPtanθThe rifle must be aimed at an angle θ=0.015 above horizontal.Height to be aimed = 30tanθ=30(θ)=30×0.015=45cm