Question

A gun is fitted on platform moving with velocity
v. = 10 m/s. A bullet is fired from the gun with
muzzle velocity v = (40î + 209) m/s with respect
to the platform. Then the horizontal range of
projectile is
12) 400 m​

Answer 1

answer : option (3) 200m

explanation : velocity of platform,$v_p$ = 10 i m/s

velocity of bullet with respect to platform, $v_{bp}$ = (40 i + 20 j) m/s

so, velocity of bullet with respect to ground, $v_b=v_{bp}+v_p$

= 40i + 20j +10i

= 50i + 20j

velocity of bullet in horizontal direction, $u_x$= 50m/s

velocity in vertical direction, $u_y$ = 20m/s

now, horizontal range, $R=\frac{2u_x.u_y}{g}$

= {2(50)(20)}/10

= 200 m

hence, horizontal range = 200m

Answer 2

Explanation:

answer : option (3) 200m

explanation : velocity of platform,v_pv

p

= 10 i m/s

velocity of bullet with respect to platform, v_{bp}v

bp

= (40 i + 20 j) m/s

so, velocity of bullet with respect to ground, v_b=v_{bp}+v_pv

b

=v

bp

+v

p

= 40i + 20j +10i

= 50i + 20j

velocity of bullet in horizontal direction, u_xu

x

= 50m/s

velocity in vertical direction, u_yu

y

= 20m/s

now, horizontal range, R=\frac{2u_x.u_y}{g}R=

g

2u

x

.u

y

= {2(50)(20)}/10

= 200 m

hence, horizontal range = 200m